问题
在运行时输入一个句子，并编写一段代码来计算句子中出现的单词的平均长度
解决方案
算法START
Step 1: declare character, int and double variables
Step 2: Enter any statement
Step 3: while loop
Check condition stmt[i]=getchar()) != ''
True then enter into loop
Increment I and call the function at step 5
Step 4: Print the average length return by function
From step 5
Step 5: called function calculatewordlength
i. declare and initialize
charcount=0 and wordcount=1
ii. while loop
check condition (*stmt != '
')
if it trues enter into loop
1. if(*stmt != ' ')
2. charcount++;
3. else if(*stmt == ' ')
4. wordcount++;
5. stmt++;
iii. return (double)charcount/wordcount;
STOP
程序
#include<stdio.h>
#include<string.h>
double calculatewordlength(const char *stmt);
int main(){
char stmt[100];
int i=0;
double avglen;
printf("enter any statement:");
while((stmt[i]=getchar()) != '')
i++;
stmt[i]='
';
avglen=calculatewordlength(stmt);
printf("average length of word is:%f.
", avglen);
}
double calculatewordlength(const char *stmt){
int charcount=0;
int wordcount=1;
while(*stmt != '
'){
if(*stmt != ' ')
charcount++;
else if(*stmt == ' ')
wordcount++;
stmt++;
}
return (double)charcount/wordcount;
}
输出
enter any statement:Tutorials Point is the best resource for online education average length of word: 5.444444444.
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