Given ‘a’ the First term, ‘d’ the common difference and ‘n’ for the number of terms in a series. The task is to find the nth term of the series.
So, before discussing how to write a program for the problem first we should know what is Arithmetic Progression.
Arithmetic progression or arithmetic sequence is a sequence of number where the difference between the two consecutive terms is same.
Like we have first term i.e a =5, difference 1 and nth term we want to find should be 3. So, the series would be: 5, 6, 7 so the output must be 7.
So, we can say that Arithmetic Progression for nth term will be like −
AP1 = a1
AP2 = a1 + (2-1) * d
AP3 = a1 + (3-1) * d
..APn = a1 + (n-1) *
So the formula will be AP = a + (n-1) * d.
Example
Input: a=2, d=1, n=5
Output: 6
Explanation: The series will be:
2, 3, 4, 5, 6 nth term will be 6
Input: a=7, d=2, n=3
Output: 11
Approach we will be using to solve the given problem −
- Take first term A, common difference D, and N the number of series.
- Then calculate nth term by (A + (N - 1) * D)
- Return the Output obtained from the above calculation.
Algorithm
Start
Step 1 -> In function int nth_ap(int a, int d, int n)
Return (a + (n - 1) * d)
Step 2 -> int main()
Declare and initialize the inputs a=2, d=1, n=5
Print The result obtained from calling the function nth_ap(a,d,n)
StopExample
#include <stdio.h>
int nth_ap(int a, int d, int n) {
// using formula to find the
// Nth term t(n) = a(1) + (n-1)*d
return (a + (n - 1) * d);
}
//main function
int main() {
// starting number
int a = 2;
// Common difference
int d = 1;
// N th term to be
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