Introduction
在C++中，字符串是一系列的字符，这些字符可以是不同的或重复的。连续的字符是同时出现的字符，它们之间的差值为1。例如，字符a和b是连续的，因为它们一起出现。然而，字符m和o在它们的位置上有一个差值为2，使它们不是连续的。
在本文中，我们将开发一段代码，该代码将以字符串作为输入，并在字符串中的所有字符连续时显示true。让我们看下面的示例以更好地理解这个主题
Sample Example
示例1 - str - “pqsr”
输出 - 是
In this article, we will develop a code to extract the current and the previous character from the string. It is then further checked if the characters differ by position non-equivalent to 1, then the boolean false value is returned.
Syntax
sort()
的翻译为：sort()
sort(str.begin(), str.end())
C++中的sort()方法用于将字符串中的字符按照从开始到结束的顺序进行增序排列。
参数
str - The input string
end - 字符串中最后出现的字符
begin-字符串中第一个出现的字符
length()
的翻译为：length()
The length() method in C++ is used to compute the number of characters in the string.
str.length()
参数
str - The input string
算法
接受一个输入字符串，str作为输入。
The input string is sorted using the sort() method.
An iteration of the string is performed, using the for loop i.
The length of the string is computed using the length() method and stored in len variable.
在字符串上执行for循环迭代，i是进行的迭代。
每次提取第ith, ch和第i-1th, ch1位置的字符。
If the difference between these two characters is not equal to 1, then a boolean false value is returned
If all the corresponding characters satisfy the required condition, then the boolean value - true is returned.
这个值以布尔标志的形式返回，存储在变量res中。如果它的值为true，则打印出包含连续字符的字符串。
Example
以下C++代码片段用于输入一个示例字符串，并计算字符串中出现的所有字符是否连续。
//including the required libraries
#include <bits/stdc++.h>
using namespace std;
//function to check of characters consecutive
bool validateString(string str) {
//length of the string
int len = str.length();
// sorting the given string
sort(str.begin(), str.end());
// Iterate for every index and
// check for the condition
for (int i = 1; i < len; i++) {
//extract characters at the required pos
char ch = str[i];
char ch1 = str[i-1];
if (ch-ch1 != 1)
//in case characters are not consecutive
return false;
}
//if condition holds
return true;
}
//calling the main method
int main() {
// 1st example
string str = "mpon";
cout << "Input String : " <<str << "
";
bool res = validateString(str);
if (res)
cout << "Yes, the string contains only consecutive characters
";
else
cout << "No, the string doesn't contain only consecutive characters.
";
return 0;
}
Output
Input String − mpon
Yes, the string contains only consecutive characters
Conclusion
字符串中不断出现的字符是同时出现的&
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