输入N，它等于要打印的系列的最大数
Input : N=5
Output : 0 ¼ ½ ¾ 1
算法
START
Step 1 -> declare start variables as int num , den, i, n
Step 2 -> input number in n
Step 3 -> Loop For from i to 0 and i<n and i++
Outer If i%2=0
Inner IF i%4=0
Set num=i/4 and den=0
End Outer IF
Else
Set num=i/2 and den=2
End Else
End Outer IF
Else
Set num = I and den = 4
End Else
If den != 0
Print num and den
End IF
Else
Print num
End Else
Step 4 -> End For Loop
STOP示例
#include <stdio.h>
int main(int argc, char const *argv[]) {
int num, den;
int i, n;
printf("Enter series limit");
scanf("%d", &n); //Till where the series will be starting from zero
for (i = 0; i < n; i++) {
if (i%2==0) { //Checking the numerator is odd or even
if(i%4==0) { //If the numerator divisible by 4 divide it
num = i/4;
den = 0;
}
else {//if not divisible by 4 its even number divisible by 2
num = i/2;
den = 2;
}
}
else { //Assigning numerator and denominator value if the number is odd
num = i;
den = 4;
}
if (den != 0) { //if denominator is not zero then print in fraaction form
printf("%d/%d
",num, den);
}
else //else print in a normal number form
printf("%d
", num);
}
return 0;
}
输出
如果我们运行上$
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